x^2-4x+540=0

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Solution for x^2-4x+540=0 equation:


Simplifying
x2 + -4x + 540 = 0

Reorder the terms:
540 + -4x + x2 = 0

Solving
540 + -4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-540' to each side of the equation.
540 + -4x + -540 + x2 = 0 + -540

Reorder the terms:
540 + -540 + -4x + x2 = 0 + -540

Combine like terms: 540 + -540 = 0
0 + -4x + x2 = 0 + -540
-4x + x2 = 0 + -540

Combine like terms: 0 + -540 = -540
-4x + x2 = -540

The x term is -4x.  Take half its coefficient (-2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
-4x + 4 + x2 = -540 + 4

Reorder the terms:
4 + -4x + x2 = -540 + 4

Combine like terms: -540 + 4 = -536
4 + -4x + x2 = -536

Factor a perfect square on the left side:
(x + -2)(x + -2) = -536

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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